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v411_ud_ratio_vpower.py
verification/v411_ud_ratio_vpower.py
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"""v411 -- The quark u/d ratio is a pure V-power readout. The established
closed form c_u/c_d = g_car ||Pl(K)||_1 / (N_fam^2 Delta_Q) = 55/117 (v94)
re-expresses EXACTLY as a quotient of three bilinear readouts of the single
sheet generator V = Q diag(0,1,1) (v410). [E] re-encoding; the physical
reading stays [C], coupled to the existing readout rigidity.
[E] 1. V-POWER FORM.
c_u/c_d = (1^T V^4 1) / ((a^T V 1)(1^T V^2 1))
= 55 / (9 * 13) = 55/117,
with 55 = 1^T V^4 1 (quark numerator), 9 = a^T V 1 = N_fam^2, and
13 = 1^T V^2 1 = Delta_Q.
[E] 2. IDENTITY TO THE ESTABLISHED FORM. This is the same number as
g_car ||Pl(K)||_1 / (N_fam^2 Delta_Q) = 5*11/(9*13) = 55/117
(v94): 55 = 5*11 = g_car * (the left-Pluecker norm of K), so the
V-power numerator simply repackages g_car*11 as 1^T V^4 1.
HONEST TYPING. This is an exact RE-ENCODING, not an independent derivation:
it adds no new physical input. The value 55/117 and which contraction IS
u/d stay [C], coupled to the wall-selection / readout rigidity (U_wall).
The gain is structural -- numerator AND denominator now come from iterating
ONE operator V. Mirrored in wolfram/tfpt_readouts_extension.wl.
"""
import sympy as sp
from tfpt_constants import check, summary, reset, g_car, N_fam
Q = sp.Matrix([[3, 1, 0], [3, 2, 0], [3, 2, 1]])
V = Q * sp.diag(0, 1, 1)
ONE = sp.Matrix([1, 1, 1])
A = sp.Matrix([1, 1, 2])
DELTA_Q = 13
PL_K = 11 # ||Pl(K)||_1 (v94 left-Pluecker norm of K)
def run():
reset()
print("v411 u/d ratio as a pure V-power readout")
num = (ONE.T * V**4 * ONE)[0]
a_v_1 = (A.T * V * ONE)[0]
o1_v2_1 = (ONE.T * V**2 * ONE)[0]
check("V-POWER FORM [E]: c_u/c_d = (1^T V^4 1)/((a^T V 1)(1^T V^2 1)) = "
"55/(9*13) = 55/117, with 55 = 1^T V^4 1, 9 = a^T V 1 = N_fam^2, "
"13 = 1^T V^2 1 = Delta_Q",
num == 55 and a_v_1 == 9 == N_fam**2 and o1_v2_1 == 13 == DELTA_Q
and sp.Rational(num, a_v_1 * o1_v2_1) == sp.Rational(55, 117))
check("IDENTITY [E]: same number as the established g_car*||Pl(K)||_1/"
"(N_fam^2*Delta_Q) = 5*11/(9*13) = 55/117 (v94); the V-power "
"numerator repackages g_car*11 = 55 = 1^T V^4 1",
sp.Rational(g_car * PL_K, N_fam**2 * DELTA_Q) == sp.Rational(55, 117)
and g_car * PL_K == 55 == num)
check("HONEST TYPING [C]: an exact RE-ENCODING, no new physical input -- "
"the value 55/117 and the u/d identification stay [C], coupled to "
"the wall-selection readout rigidity (U_wall); the gain is that "
"numerator and denominator both iterate ONE operator V",
True)
return summary("v411 u/d ratio = (1^TV^4 1)/((a^TV1)(1^TV^2 1)) = 55/117")
if __name__ == "__main__":
raise SystemExit(1 if run() else 0)
Recorded source fingerprint
640df91647fd95ff6ebe80c7e6f521a7803c4c9e1ab5d96db6534ae151eb50ca
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