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v809_curve_code_doily.py
verification/v809_curve_code_doily.py
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#!/usr/bin/env python3
# -*- coding: utf-8 -*-
r"""v809 -- CURVE.CODE.DOILY.01: the certified outer bridge sharpened into an incidence-operator statement with a spectral payoff, one probe (21/21 checks incl. the 3 must-fire controls, ~1 s; discovery probe curve_code_doily_probe.py, 2026-08-06, verdict DOILY-EXACT). THE EXACT IDENTITY: the K6 doily incidence N (15 duads x 15 synthemes on the six odd Arf refinements) satisfies NN^T = 3I + A_KG(6,2) = B + 2I entrywise, with B the certified v752/v774 symplectic incidence (synthemes <-> isotropic lines bijectively; row and column sums 3; two duads share a syntheme iff disjoint, then exactly one). THE SPECTRAL PAYOFF: spec(NN^T) = spec(N^T N) = {9^1, 4^9, 0^5} exact (annihilating polynomial + traces + rank over Q), so the normalized channel N/3 has singular values {1, 2/3, 0} -- THE RECOVERY BASE RATE 2/3 (v221) as the unique nontrivial singular value of the canonical duad-to-syntheme incidence; the identification with the corpus rate (2/3)^6 = 64/729 is TYPED [H neu -> decidable, not decided here]: it requires the six-step composition semantics (the hexagon). PETERSEN LOCALIZATION: at the q*-distinguished point the 15 duads split 5 + 10, the 10 internal duads form the Petersen graph, and syntheme -> internal pair is a BIJECTION onto E(Petersen) 15/15 -- Petersen vertices = code duads, Petersen edges = curve synthemes under the certified bridge. THE REFINED BRIDGE: every census bridge (rebuilt with the frozen BRIDGE-CANONICAL conditions, census 6) factors EXACTLY through N -- Delta(d) = {Gamma(s) : d in s} and the matrix identity N_code = P_Delta^T N_curve^T P_Gamma: the outer bridge conjugates the code incidence to the TRANSPOSE of the curve incidence, a DUALITY, not an isomorphism (control C3: 720 symplectic isomorphisms exist, 0 intertwine sigma with tau -- the inner route stays dead). THE ARF LAYER in doily coordinates: the switch set T6 = the six within-block duads of the q_Theta point-split, bijective onto the 6 odd theta characteristics -- the census-6 anchor. N/3 is doubly stochastic (typed CLASSICAL incidence channel, not CPTP; 1 + 9 + 5 spectral decomposition, rate 2/3 on the 9-dim window) -- measured, no descent claim. No matter semantics (ROOTCLASS-MIXED, v775); the inner identification stays CURVE-CODE-PARTIAL/dead. No marker move, NO RH claim. Python-only per GATE.WOLFRAM.02.
PROVENANCE: discovery probe curve_code_doily_probe.py (2026-08-06, 21/21, ~1 s, DOILY-EXACT; no spec corrections disclosed); re-run identically at promotion. Promoted verbatim, the script-style probe body wrapped in a function scope (v789/v795 precedent); a module-level _LAST verdict capture inserted (v791 precedent); numbers unchanged; run() encodes the pattern (v757 precedent).
Original curve_code_doily_probe.py docstring (verbatim):
curve_code_doily_probe -- CURVE.CODE.DOILY.01: the certified outer
bridge (duad_syntheme_bridge_probe, BRIDGE-CANONICAL, 24/24) sharpened
into an incidence-operator statement with a spectral payoff.
FROZEN CLAIMS:
1. DOILY INCIDENCE. On the 6 points (= the six Arf-1 refinements of
the code side), 15 duads and 15 synthemes with N_{d,s} = [d in s].
Each duad lies in exactly 3 synthemes; two duads share a syntheme
iff disjoint (then exactly one). Hence the EXACT matrix identity
N N^T = 3I + A_{KG(6,2)} = B + 2I,
where B = I + A_{KG(6,2)} is the certified v752/v774 symplectic
incidence (B[x][y] = [hbar(x,y) = 0] under the K6 duad dictionary
v <-> D(v)); synthemes <-> isotropic lines bijectively.
2. SPECTRAL PAYOFF. spec(N N^T) = {9^1, 4^9, 0^5} (from the v774
charpoly (x-7)(x-2)^9(x+2)^5 of B, shifted by +2); the normalized
point-to-line channel N/3 has singular values {1, 2/3^(x9), 0^(x5)}
-- THE RECOVERY BASE RATE 2/3 as the unique nontrivial singular
value of the canonical duad-to-syntheme incidence.
TYPED IDENTIFICATION [H neu -> decidable, NOT decided here]: the
corpus recovery rate is (2/3)^6 = 64/729 (v221 seam recoverability
code, spectrum {1,(2/3)^6,(1/3)^6} from cusp weights {0,1/3,2/3}
and the SIX-fold transfer (1-w)^6; v240 OS gap Delta = 6 ln(3/2);
v425 native flow e^{-Delta} = (2/3)^6). The doily channel supplies
the PER-STEP number 2/3 exactly; identification with the corpus
rate additionally requires the six-step composition semantics (the
hexagon; conceptually the C6 = distance-2 shell of the parallel
Petersen probe -- cited as a pointer only, NOTHING here depends on
its output). This probe verifies the number and TYPES the gap.
3. PETERSEN LOCALIZATION. With the q*-distinguished point the 15
duads split 5 + 10 (5bar = duads at q* = {q*(v) = 0}\{0}; internal
10 = {q*(v) = 1} = Petersen vertices, adjacency = disjointness,
3-regular, 15 edges, girth 5). Each syntheme contains exactly one
distinguished-point duad and one disjoint internal pair = a
Petersen EDGE; syntheme -> internal pair is a BIJECTION onto
E(Petersen). Petersen vertices = code duads, Petersen edges =
(under the bridge) curve synthemes: the incidence object BETWEEN
the two sides.
4. REFINED BRIDGE. For every census bridge beta (rebuilt here with
the identical frozen conditions: beta sigma = tau beta, beta(q*) =
S* the unique <tau, rho>-fixed spread; census must again be 6 per
family), the induced duality has two components Delta (code duads
-> curve lines) and Gamma (code synthemes -> curve points, the
unique common point of {Delta(d) : d in s}), and the factorization
Delta(d) = { Gamma(s) : N[d][s] = 1 } (exact, all d)
reproduces the bridge; equivalently the EXACT matrix identity
N_code = P_Delta^T N_curve^T P_Gamma
-- the outer bridge conjugates the code incidence to the TRANSPOSE
of the curve incidence (a duality, not an isomorphism). The Arf
translation layer re-verified in doily coordinates: the switch set
T6 = {t != 0 : q_Theta(t) = 1} has |T6| = 6, q_Theta + e2(t, .) is
odd exactly for t in T6, t -> shifted form is a bijection onto the
six odd theta characteristics, and T6 = the six WITHIN-BLOCK duads
of the q_Theta point-split (the two triangles) -- the census-6
anchor in doily coordinates.
5. INTERTWINER CANDIDATE (reported, measured -- NO descent claim):
N/3 is a doubly stochastic (unital, row and column sums 1)
classical incidence channel; N^T N has the same spectrum
{9^1, 4^9, 0^5}; both compositions (N N^T)/9 and (N^T N)/9 have
spectrum {1, (2/3)^2 x9, 0 x5}: a rank-10 channel with a 1-dim
fixed space (uniform), a 9-dim window contracted by exactly 2/3
per application, and a 5-dim annihilated complement. What it
OFFERS for the prime front: a canonical, basis-free carrier
intertwiner between the duad register (code side) and the syntheme
register (= the curve side of the certified outer bridge) whose
unique nontrivial rate is the recovery base rate. What it does
NOT provide (typed): CPTP on a quantum register (it is classical
stochastic on the 15-dim function space), and the sixth power.
CONTROLS (must fire):
C1 wrong incidence (one membership bit flipped): row/column sums
break and N N^T != B + 2I.
C2 scrambled synthemes (frozen deterministic corruption: in each
syntheme replace the lex-highest duad by the lex-next duad that
meets another member): the Petersen edge bijection breaks.
C3 inner recomposition: census of point-to-point symplectic
isomorphisms g: V -> A[2] with g sigma = tau g is 0 (the earlier
inner kill; only the outer/transpose route exists).
VERDICT ENUM (frozen): DOILY-EXACT (all identities exact, spectra
exact, Petersen bijection 15/15, refactorization exact for the full
census, Arf layer verified, controls fire; the 2/3 identification
typed with its exact requirement = six-step composition) /
DOILY-PARTIAL (incidence core holds, a named layer fails) /
DOILY-DEAD (the core identity N N^T = B + 2I fails). TEST-VOID on
control failure.
FENCES: finite exact algebra (integers/Fractions; no floats in any
load-bearing check); the curve side is the certified exact model of
curve_code_2torsion_probe (periods certified there at dps 120); NO
matter semantics (ROOTCLASS-MIXED, v775, stands); the inner
identification stays dead (CURVE-CODE-PARTIAL); nothing here modifies
the corpus recovery modules v221/v240/v425 -- claim 2 is a typed
cross-reference, not a re-derivation. EXPLORATION ONLY: one new file
in experiments/tfpt-discovery/, report only, no promotion.
Run:
experiments/tfpt-discovery/.venv/bin/python \
experiments/tfpt-discovery/curve_code_doily_probe.py
"""
_LAST = {}
import itertools
import time
from fractions import Fraction
T0 = time.time()
CHECKS = []
KILLS = []
def check(name, ok, detail="", kill=None):
CHECKS.append((name, bool(ok)))
if kill and not ok:
KILLS.append(kill)
print("[%s] %s%s" % ("PASS" if ok else "FAIL", name,
(" -- " + detail) if detail else ""), flush=True)
return bool(ok)
def section(title):
print("=" * 78)
print(title)
print("=" * 78, flush=True)
# ======================================================================
# frozen machinery (identical to duad_syntheme_bridge_probe)
# ======================================================================
ZPOW = [(1, 0, 0, 0), (0, 1, 0, 0), (0, 0, 1, 0), (0, 0, 0, 1),
(-1, 0, 1, 0), (0, -1, 0, 1), (-1, 0, 0, 0)]
CONJ_BASIS = [(1, 0, 0, 0), (0, 1, 0, -1), (1, 0, -1, 0), (0, 0, 0, -1)]
E_K = [(1, 0, 0, 0), (0, 1, 0, 0), (0, 0, 1, 0), (0, 0, 0, 1)]
def kmul(a, b):
conv = [0] * 7
for i in range(4):
if a[i]:
for j in range(4):
conv[i + j] += a[i] * b[j]
out = [0, 0, 0, 0]
for k in range(7):
if conv[k]:
for t in range(4):
out[t] += conv[k] * ZPOW[k][t]
return tuple(out)
def kconj(a):
out = [0, 0, 0, 0]
for i in range(4):
if a[i]:
for t in range(4):
out[t] += a[i] * CONJ_BASIS[i][t]
return tuple(out)
def ktrace(a):
return 4 * a[0] + 2 * a[2]
def kpow_zeta(k):
out = (1, 0, 0, 0)
for _ in range(k % 12):
out = kmul(out, (0, 1, 0, 0))
return out
def mult_matrix_mod2(g):
return [[kmul(g, E_K[j])[i] % 2 for j in range(4)] for i in range(4)]
def Estar(x, y):
t = ktrace(kmul(kmul(kpow_zeta(3), x), kconj(y)))
assert t % 2 == 0
return t // 2
def build_tables(gram):
tab = [[0] * 16 for _ in range(16)]
for x in range(16):
for y in range(16):
xv = [(x >> k) & 1 for k in range(4)]
yv = [(y >> k) & 1 for k in range(4)]
tab[x][y] = sum(xv[i] * gram[i][j] * yv[j]
for i in range(4) for j in range(4)) % 2
return tab
def all_refinements(tab):
refs = []
for mask in range(1 << 16):
q = [(mask >> i) & 1 for i in range(16)]
ok = True
for i in range(16):
row = tab[i]
qi = q[i]
for j in range(16):
if q[i ^ j] ^ qi ^ q[j] != row[j]:
ok = False
break
if not ok:
break
if ok:
refs.append(tuple(q))
return refs
def iso_lines(tab):
out = set()
for a in range(1, 16):
for b in range(a + 1, 16):
if tab[a][b] == 0 and (a ^ b) != 0:
out.add(frozenset({a, b, a ^ b}))
return sorted(out, key=sorted)
def spreads_of(lines):
pts = set(range(1, 16))
by_pt = {}
for L in lines:
for p in L:
by_pt.setdefault(p, []).append(L)
def rec(cov, used):
if len(cov) == 15:
return [frozenset(used)]
p = min(pts - cov)
res = []
for L in by_pt[p]:
if cov & L:
continue
res += rec(cov | L, used + [L])
return res
return sorted(set(rec(frozenset(), [])),
key=lambda S: sorted(map(sorted, S)))
def linear_transporters(src_tab, dst_tab):
out = []
for m in range(1 << 16):
cols = [(m >> (4 * k)) & 15 for k in range(4)]
img = [0] * 16
for x in range(16):
v = 0
for k in range(4):
if x & (1 << k):
v ^= cols[k]
img[x] = v
if len(set(img)) != 16:
continue
ok = True
for x in range(1, 16):
for y in range(x, 16):
if dst_tab[img[x]][img[y]] != src_tab[x][y]:
ok = False
break
if not ok:
break
if ok:
out.append(tuple(img))
return out
def inv_perm16(g):
gi = [0] * 16
for x in range(16):
gi[g[x]] = x
return gi
class Side(object):
def __init__(self, name, gram):
self.name = name
self.tab = build_tables(gram)
self.refs = all_refinements(self.tab)
zeros = {q: sum(1 for b in q if b == 0) for q in self.refs}
self.odds = sorted(q for q in self.refs if zeros[q] == 6)
self.evens = sorted(q for q in self.refs if zeros[q] == 10)
self.lines = iso_lines(self.tab)
self.spreads = spreads_of(self.lines)
self.duad_of = {} # vector -> frozenset of 2 odd indices
self.duad_vec = {} # frozenset of 2 odd indices -> vector
for v in range(1, 16):
dv = frozenset(i for i, q in enumerate(self.odds) if q[v] == 0)
assert len(dv) == 2
self.duad_of[v] = dv
self.duad_vec[dv] = v
self.shared = {}
for i in range(6):
for j in range(i + 1, 6):
inter = self.spreads[i] & self.spreads[j]
assert len(inter) == 1
self.shared[frozenset({i, j})] = inter
def odd_perm(self, g):
gi = inv_perm16(g)
return [self.odds.index(tuple(q[gi[v]] for v in range(16)))
for q in self.odds]
def spread_perm(self, g):
out = []
for S in self.spreads:
Sg = frozenset(frozenset(g[p] for p in L) for L in S)
out.append(self.spreads.index(Sg))
return out
def split_pts(self, q):
adj = {i: set() for i in range(6)}
for i in range(6):
for j in range(i + 1, 6):
if q[self.duad_vec[frozenset({i, j})]] == 1:
adj[i].add(j)
adj[j].add(i)
comp, seen = [], set()
for s in range(6):
if s in seen:
continue
blk, stack = set(), [s]
while stack:
u = stack.pop()
if u in blk:
continue
blk.add(u)
stack += list(adj[u] - blk)
seen |= blk
comp.append(frozenset(blk))
return frozenset(comp)
def mat_mul(A, Bm):
n, m, p = len(A), len(Bm), len(Bm[0])
out = [[0] * p for _ in range(n)]
for i in range(n):
Ai = A[i]
for k in range(m):
a = Ai[k]
if a:
Bk = Bm[k]
Oi = out[i]
for j in range(p):
Oi[j] += a * Bk[j]
return out
def mat_rank_q(M):
A = [[Fraction(x) for x in row] for row in M]
n, m = len(A), len(A[0])
rank, row = 0, 0
for col in range(m):
piv = None
for r in range(row, n):
if A[r][col] != 0:
piv = r
break
if piv is None:
continue
A[row], A[piv] = A[piv], A[row]
pv = A[row][col]
A[row] = [x / pv for x in A[row]]
for r in range(n):
if r != row and A[r][col] != 0:
f = A[r][col]
A[r] = [x - f * y for x, y in zip(A[r], A[row])]
row += 1
rank += 1
if row == n:
break
return rank
def spectrum_945(M, label):
"""certify spec(M) = {9^1, 4^9, 0^5} exactly (integer arithmetic)."""
n = len(M)
I = [[int(i == j) for j in range(n)] for i in range(n)]
M4 = [[M[i][j] - 4 * I[i][j] for j in range(n)] for i in range(n)]
M9 = [[M[i][j] - 9 * I[i][j] for j in range(n)] for i in range(n)]
annih = mat_mul(mat_mul(M, M4), M9)
ann_ok = all(x == 0 for row in annih for x in row)
tr1 = sum(M[i][i] for i in range(n))
M2 = mat_mul(M, M)
tr2 = sum(M2[i][i] for i in range(n))
rk = mat_rank_q(M)
# eigenvalues in {0,4,9}; m9*9 + m4*4 = tr1, m9*81 + m4*16 = tr2,
# m9 + m4 = rank -> unique solution (1, 9, 5)
ok = (ann_ok and tr1 == 45 and tr2 == 225 and rk == 10)
print(" %s: annihilator M(M-4)(M-9)=0: %s; tr=%d tr2=%d rank=%d"
% (label, ann_ok, tr1, tr2, rk))
return ok
# ======================================================================
# S1 -- the doily incidence N and the exact identity NN^T = B + 2I
# ======================================================================
def main():
"""Probe body, promoted verbatim in a function scope (v789/v795 precedent; the probe is script-style)."""
section("S1: doily incidence N (15 duads x 15 synthemes) and the exact "
"identity NN^T = 3I + A_KG = B + 2I (v752/v774 object)")
GJI = [[0, 1, 1, 1], [1, 0, 1, 1], [1, 1, 0, 1], [1, 1, 1, 0]]
SIG_B = [0] * 16
for x in range(16):
b = [(x >> k) & 1 for k in range(4)]
nb = (b[2], b[0], b[1], b[3])
SIG_B[x] = nb[0] | (nb[1] << 1) | (nb[2] << 2) | (nb[3] << 3)
code = Side("code", GJI)
DUADS = sorted(map(sorted, itertools.combinations(range(6), 2)))
DUADS = [frozenset(d) for d in DUADS]
SYNTHEMES = []
for m in itertools.combinations(DUADS, 3):
if len(m[0] | m[1] | m[2]) == 6:
SYNTHEMES.append(frozenset(m))
SYNTHEMES.sort(key=lambda s: sorted(map(sorted, s)))
check("S1.1 K6 census: 15 duads, %d synthemes (perfect matchings)"
% len(SYNTHEMES), len(SYNTHEMES) == 15, kill="K")
# syntheme <-> isotropic line dictionary
syn_line = {}
for s in SYNTHEMES:
trip = frozenset(code.duad_vec[d] for d in s)
match = [L for L in code.lines if frozenset(L) == trip]
syn_line[s] = match[0] if len(match) == 1 else None
check("S1.2 synthemes <-> isotropic lines BIJECTIVE via the duad "
"dictionary v <-> D(v): every matching is an isotropic line and "
"all 15 lines are hit",
all(v is not None for v in syn_line.values())
and len(set(map(frozenset, syn_line.values()))) == 15, kill="K")
N = [[1 if DUADS[i] in SYNTHEMES[j] else 0 for j in range(15)]
for i in range(15)]
rows3 = all(sum(N[i]) == 3 for i in range(15))
cols3 = all(sum(N[i][j] for i in range(15)) == 3 for j in range(15))
check("S1.3 each duad lies in exactly 3 synthemes and each syntheme "
"contains exactly 3 duads (row and column sums 3)",
rows3 and cols3, kill="K")
NNt = mat_mul(N, [list(r) for r in zip(*N)])
share_ok = True
for i in range(15):
for j in range(15):
dis = (i != j and not (DUADS[i] & DUADS[j]))
want = 3 if i == j else (1 if dis else 0)
if NNt[i][j] != want:
share_ok = False
check("S1.4 two duads share a syntheme iff DISJOINT, then exactly one: "
"NN^T = 3I + A_KG(6,2) entrywise", share_ok, kill="K")
Bmat = [[1 if code.tab[code.duad_vec[DUADS[i]]][code.duad_vec[DUADS[j]]]
== 0 else 0 for j in range(15)] for i in range(15)]
b_id = all(NNt[i][j] == Bmat[i][j] + 2 * (i == j)
for i in range(15) for j in range(15))
kg_id = all(Bmat[i][j] == (1 if (i == j or not (DUADS[i] & DUADS[j]))
else 0) for i in range(15) for j in range(15))
check("S1.5 EXACT MATRIX IDENTITY: NN^T == B + 2I where B[x][y] = "
"[hbar(x,y) = 0] is the certified v752/v774 symplectic incidence, "
"and B == I + A_KG entrywise (re-verified)", b_id and kg_id,
kill="K")
# ======================================================================
# S2 -- spectra and the 2/3 payoff (typed identification)
# ======================================================================
section("S2: spectra -- spec(NN^T) = {9,4^9,0^5}, singular values of "
"N/3 = {1, 2/3, 0}; the corpus (2/3)^6 cross-check TYPED")
Nt = [list(r) for r in zip(*N)]
NtN = mat_mul(Nt, N)
ok_a = spectrum_945(NNt, "NN^T (duad side)")
ok_b = spectrum_945(NtN, "N^T N (syntheme side)")
check("S2.1 spec(NN^T) = spec(N^T N) = {9^1, 4^9, 0^5} EXACT "
"(annihilating polynomial + traces + rank over Q; consistent with "
"v774 charpoly of B = (x-7)(x-2)^9(x+2)^5 shifted by +2)",
ok_a and ok_b, kill="K")
sv2 = sorted({Fraction(e, 9) for e in (9, 4, 0)}, reverse=True)
check("S2.2 singular values of the normalized channel N/3: squared "
"values {1, 4/9, 0} -> {1, 2/3, 0}: THE RECOVERY BASE RATE 2/3 is "
"the unique nontrivial singular value of the duad-to-syntheme "
"incidence", sv2 == [Fraction(1), Fraction(4, 9), Fraction(0)],
kill="K")
rate6 = Fraction(2, 3) ** 6
check("S2.3 corpus cross-check EXACT AT NUMBER LEVEL: (2/3)^6 = %s = "
"64/729 = the v221 seam recovery rate ((1-w)^6 at cusp weight "
"w = 1/3; v240 OS gap Delta = 6 ln(3/2); v425 native flow)"
% rate6, rate6 == Fraction(64, 729), kill="K")
print(" TYPED [H neu -> decidable, NOT decided here]: the doily")
print(" channel supplies the PER-STEP 2/3; identification with the")
print(" corpus rate requires the SIX-step composition semantics")
print(" (the hexagon / C6 = distance-2 shell of the parallel")
print(" Petersen probe -- conceptual pointer only, no dependence).")
# ======================================================================
# S3 -- Petersen localization at q*
# ======================================================================
section("S3: Petersen localization at the q*-distinguished point")
QSTAR = [q for q in code.odds
if all(q[SIG_B[x]] == q[x] for x in range(16))
and q[0b1000] == 1 and q[0b0111] == 0]
assert len(QSTAR) == 1
QSTAR = QSTAR[0]
qs_idx = code.odds.index(QSTAR)
at_q = [i for i, d in enumerate(DUADS) if qs_idx in d]
internal = [i for i, d in enumerate(DUADS) if qs_idx not in d]
split_ok = (len(at_q) == 5 and len(internal) == 10
and all(QSTAR[code.duad_vec[DUADS[i]]] == 0 for i in at_q)
and all(QSTAR[code.duad_vec[DUADS[i]]] == 1
for i in internal))
check("S3.1 duad split 5 + 10 at q*: the 5 duads at q* = the 5bar words "
"{q* = 0}\\{0}; the 10 internal duads = the 10 words {q* = 1}",
split_ok, kill="K")
pet_adj = {i: set() for i in internal}
for i in internal:
for j in internal:
if i != j and not (DUADS[i] & DUADS[j]):
pet_adj[i].add(j)
n_edges = sum(len(v) for v in pet_adj.values()) // 2
def girth(adj):
best = None
for s in adj:
dist, par = {s: 0}, {s: None}
queue = [s]
while queue:
u = queue.pop(0)
for w in adj[u]:
if w not in dist:
dist[w] = dist[u] + 1
par[w] = u
queue.append(w)
elif par[u] != w:
c = dist[u] + dist[w] + 1
if best is None or c < best:
best = c
return best
check("S3.2 internal graph (adjacency = disjointness) IS Petersen: 10 "
"vertices, 3-regular, %d edges, girth %d (3-regular girth-5 on 10 "
"vertices is Petersen, Moore uniqueness)"
% (n_edges, girth(pet_adj)),
all(len(v) == 3 for v in pet_adj.values()) and n_edges == 15
and girth(pet_adj) == 5, kill="K")
syn_edge = {}
pet_ok = True
for j, s in enumerate(SYNTHEMES):
dq = [d for d in s if qs_idx in d]
di = [d for d in s if qs_idx not in d]
if not (len(dq) == 1 and len(di) == 2 and not (di[0] & di[1])):
pet_ok = False
continue
syn_edge[j] = frozenset({DUADS.index(di[0]), DUADS.index(di[1])})
edges = {frozenset({i, j}) for i in pet_adj for j in pet_adj[i]}
bij_ok = (len(syn_edge) == 15
and set(syn_edge.values()) == edges
and len(set(syn_edge.values())) == 15)
check("S3.3 PETERSEN EDGE BIJECTION: every syntheme = one q*-duad + one "
"disjoint internal pair; syntheme -> internal pair is a bijection "
"onto the 15 Petersen edges (census %d/15 valid, %d/15 distinct)"
% (len(syn_edge), len(set(syn_edge.values()))),
pet_ok and bij_ok, kill="K")
# ======================================================================
# S4 -- the refined bridge: factorization through N
# ======================================================================
section("S4: refined bridge -- the census bridges factor through N "
"(N_code = P_Delta^T N_curve^T P_Gamma)")
ESTAR = [[Estar(E_K[i], E_K[j]) % 2 for j in range(4)] for i in range(4)]
MT = mult_matrix_mod2(kpow_zeta(4))
MR = mult_matrix_mod2(kpow_zeta(9))
TAU_B = [0] * 16
RHO_B = [0] * 16
for x in range(16):
xv = [(x >> k) & 1 for k in range(4)]
it = [sum(MT[i][j] * xv[j] for j in range(4)) % 2 for i in range(4)]
ir = [sum(MR[i][j] * xv[j] for j in range(4)) % 2 for i in range(4)]
TAU_B[x] = it[0] | (it[1] << 1) | (it[2] << 2) | (it[3] << 3)
RHO_B[x] = ir[0] | (ir[1] << 1) | (ir[2] << 2) | (ir[3] << 3)
curve = Side("curve", ESTAR)
code.sp = linear_transporters(code.tab, code.tab)
sigO = code.odd_perm(SIG_B)
tauT = curve.spread_perm(TAU_B)
rhoT = curve.spread_perm(RHO_B)
S_STAR_SET = [i for i in range(6) if tauT[i] == i and rhoT[i] == i]
assert len(S_STAR_SET) == 1
S_STAR = S_STAR_SET[0]
FULL_tau = [beta for beta in itertools.permutations(range(6))
if all(beta[sigO[i]] == tauT[beta[i]] for i in range(6))
and beta[qs_idx] == S_STAR]
check("S4.1 census bridges rebuilt with the identical frozen "
"conditions: %d (must be 6, the BRIDGE-CANONICAL torsor)"
% len(FULL_tau), len(FULL_tau) == 6, kill="K")
N_curve = [[1 if p in L else 0 for L in curve.lines]
for p in range(1, 16)] # 15 points x 15 lines
fact_ok = True
matid_ok = True
petersen_bridge_ok = True
for beta in FULL_tau:
Delta = {}
for v in range(1, 16):
i, j = sorted(beta[i] for i in code.duad_of[v])
(L,) = curve.shared[frozenset({i, j})]
Delta[v] = L
Gamma = {}
for s_idx, s in enumerate(SYNTHEMES):
pts = None
for d in s:
P = set(Delta[code.duad_vec[d]])
pts = P if pts is None else (pts & P)
if pts is None or len(pts) != 1:
fact_ok = False
continue
Gamma[s_idx] = pts.pop()
# factorization Delta(d) = {Gamma(s) : d in s}
for i, d in enumerate(DUADS):
v = code.duad_vec[d]
img = {Gamma[j] for j in range(15) if N[i][j] == 1}
if img != set(Delta[v]):
fact_ok = False
# matrix identity N_code[d][s] == N_curve[Gamma(s)][Delta(d)]
for i, d in enumerate(DUADS):
v = code.duad_vec[d]
Lidx = curve.lines.index(Delta[v])
for j in range(15):
if N[i][j] != N_curve[Gamma[j] - 1][Lidx]:
matid_ok = False
# Petersen blocks under the bridge: 5bar duads -> lines of S*,
# internal (Petersen vertex) duads -> the 10 non-S* lines
img5 = {Delta[code.duad_vec[DUADS[i]]] for i in at_q}
img10 = {Delta[code.duad_vec[DUADS[i]]] for i in internal}
if img5 != set(curve.spreads[S_STAR]) or \
img10 != set(curve.lines) - set(curve.spreads[S_STAR]):
petersen_bridge_ok = False
check("S4.2 FACTORIZATION exact for all 6 census bridges: Gamma(s) = "
"the unique common curve point of {Delta(d) : d in s}, and "
"Delta(d) = {Gamma(s) : N[d][s] = 1} for every duad -- the bridge "
"IS 'apply N, then the outer duality on synthemes'", fact_ok,
kill="K")
check("S4.3 EXACT MATRIX IDENTITY for all 6 census bridges: N_code = "
"P_Delta^T N_curve^T P_Gamma -- the outer bridge conjugates the "
"code incidence to the TRANSPOSE of the curve incidence (a "
"duality, not an isomorphism)", matid_ok, kill="K")
check("S4.4 Petersen blocks transport: the 5 duads at q* -> the 5 lines "
"of S*, the 10 Petersen vertices -> the 10 non-S* lines (all "
"census bridges) -- Petersen vertices = code duads, Petersen "
"edges = curve synthemes", petersen_bridge_ok, kill="K")
# Arf translation layer in doily coordinates (curve side)
QTHETA = [q for q in curve.refs
if all(q[TAU_B[x]] == q[x] for x in range(16))]
assert len(QTHETA) == 1
QTHETA = QTHETA[0]
T6 = [t for t in range(1, 16) if QTHETA[t] == 1]
shift_odds = {}
arf_layer_ok = len(T6) == 6
for t in range(1, 16):
qt = tuple((QTHETA[x] + curve.tab[t][x]) % 2 for x in range(16))
is_odd = qt in curve.odds
if t in T6:
if not is_odd:
arf_layer_ok = False
shift_odds[t] = qt
else:
if is_odd:
arf_layer_ok = False
arf_layer_ok = arf_layer_ok and sorted(shift_odds.values()) == curve.odds
split_qT = curve.split_pts(QTHETA)
within = set()
for blk in split_qT:
for pair in itertools.combinations(sorted(blk), 2):
within.add(curve.duad_vec[frozenset(pair)])
check("S4.5 ARF TRANSLATION LAYER in doily coordinates: |T6| = %d "
"switch points {q_Theta = 1}; q_Theta + e2(t, .) is odd EXACTLY "
"for t in T6 and t -> shifted form is a bijection onto the 6 odd "
"theta characteristics; T6 == the 6 WITHIN-BLOCK duads of the "
"q_Theta point-split (the two triangles) -- the census-6 anchor"
% len(T6), arf_layer_ok and within == set(T6), kill="K")
# ======================================================================
# S5 -- the intertwiner candidate (reported, measured)
# ======================================================================
section("S5: the intertwiner candidate N/3 (reported, measured -- no "
"descent claim)")
ds_ok = (all(sum(Fraction(x, 3) for x in N[i]) == 1 for i in range(15))
and all(sum(Fraction(N[i][j], 3) for i in range(15)) == 1
for j in range(15)))
check("S5.1 N/3 is DOUBLY STOCHASTIC (unital classical channel on the "
"15-dim function space): all row and column sums exactly 1",
ds_ok, kill="K")
check("S5.2 both compositions have spectrum {1, (2/3)^2 x9, 0 x5}: "
"1-dim fixed space (uniform), 9-dim window contracted by exactly "
"2/3 per application, 5-dim annihilated complement (rank 10)",
ok_a and ok_b, kill="K")
print(" OFFERED for the prime front (measured): a canonical,")
print(" basis-free carrier intertwiner between the duad register")
print(" (code side) and the syntheme register (= the curve side of")
print(" the certified outer bridge), unique nontrivial rate = the")
print(" recovery base rate 2/3 on the 9-dim window.")
print(" NOT PROVIDED (typed): CPTP on a quantum register (this is")
print(" classical stochastic incidence), and the sixth power --")
print(" the six-step composition is the open identification of S2.")
# ======================================================================
# S6 -- controls
# ======================================================================
section("S6: controls")
N_bad = [row[:] for row in N]
N_bad[0][0] ^= 1
NNt_bad = mat_mul(N_bad, [list(r) for r in zip(*N_bad)])
c1 = (sum(N_bad[0]) != 3 or sum(N_bad[i][0] for i in range(15)) != 3) \
and any(NNt_bad[i][j] != Bmat[i][j] + 2 * (i == j)
for i in range(15) for j in range(15))
check("C1 FIRES: one flipped membership bit breaks the count-3 "
"structure AND NN^T != B + 2I", c1, kill="K7")
scr_ok_cols = 0
for s in SYNTHEMES:
ds = sorted(map(sorted, s))
keep = [frozenset(d) for d in ds[:2]]
top = frozenset(ds[2])
repl = None
for d in DUADS:
if d != top and d not in keep and (d & keep[0]):
repl = d
break
scr = keep + [repl]
dq = [d for d in scr if qs_idx in d]
di = [d for d in scr if qs_idx not in d]
if len(dq) == 1 and len(di) == 2 and not (di[0] & di[1]):
scr_ok_cols += 1
check("C2 FIRES: scrambled synthemes (lex-highest duad replaced by a "
"MEETING duad, frozen rule): only %d/15 corrupted synthemes still "
"satisfy the Petersen-edge property (bijection broken)"
% scr_ok_cols, scr_ok_cols < 15, kill="K7")
inner = linear_transporters(code.tab, curve.tab)
n_inner_eq = sum(1 for g in inner
if all(g[SIG_B[x]] == TAU_B[g[x]] for x in range(16)))
check("C3 FIRES: inner recomposition -- %d symplectic isomorphisms "
"V -> A[2] exist but %d intertwine sigma with tau (the inner "
"route stays DEAD; only the outer/transpose factorization exists)"
% (len(inner), n_inner_eq),
len(inner) == 720 and n_inner_eq == 0, kill="K7")
# ======================================================================
# S7 -- verdict (frozen rule)
# ======================================================================
section("S7: VERDICT (frozen enum: DOILY-EXACT / DOILY-PARTIAL / "
"DOILY-DEAD; TEST-VOID on control failure)")
n_pass = sum(1 for _, ok in CHECKS if ok)
n_tot = len(CHECKS)
controls_ok = all(ok for nm, ok in CHECKS if nm.startswith("C"))
core_ok = all(ok for nm, ok in CHECKS if nm.startswith("S1"))
print("%d/%d checks passed" % (n_pass, n_tot))
if not controls_ok:
verdict = "TEST-VOID"
elif not core_ok:
verdict = "DOILY-DEAD"
elif n_pass == n_tot:
verdict = "DOILY-EXACT"
else:
verdict = "DOILY-PARTIAL"
_LAST["verdict"] = verdict
print("VERDICT: %s" % verdict)
if verdict == "DOILY-EXACT":
print()
print("RECOMMENDED CONTRACT TEXT (exploration grade -- promotion is")
print("a separate decision):")
print(" * The K6 doily incidence N (15 duads x 15 synthemes) on the")
print(" six odd refinements satisfies NN^T = B + 2I exactly, with")
print(" B the certified v752/v774 symplectic incidence; spec =")
print(" {9, 4^9, 0^5} and the normalized channel N/3 has singular")
print(" values {1, 2/3, 0}: the recovery base rate 2/3 (v221) is")
print(" the unique nontrivial singular value of the canonical")
print(" duad-to-syntheme map. Identification with the corpus")
print(" rate (2/3)^6 requires the six-step composition semantics")
print(" [H neu -> decidable, typed, not decided here].")
print(" * At the q*-point the 10 internal duads form the Petersen")
print(" graph and syntheme -> internal pair is a bijection onto")
print(" E(Petersen): Petersen vertices = code duads, Petersen")
print(" edges = curve synthemes under the certified bridge.")
print(" * Every census bridge factors EXACTLY through N:")
print(" Delta(d) = {Gamma(s) : d in s} and N_code = P_Delta^T")
print(" N_curve^T P_Gamma -- the outer bridge is transpose-")
print(" conjugation of the incidence channel; the Arf layer is")
print(" the 6-point switch set T6 = within-block duads of the")
print(" q_Theta split.")
print(" * N/3 is a doubly stochastic carrier intertwiner (1 + 9 +")
print(" 5 spectral decomposition, rate 2/3 on the window) --")
print(" measured; no CPTP/quantum or descent claim.")
print(" * NO matter semantics (ROOTCLASS-MIXED, v775, stands); the")
print(" inner identification stays CURVE-CODE-PARTIAL/dead.")
print("Runtime: %.1f s" % (time.time() - T0))
print("ALL CHECKS PASSED" if n_pass == n_tot
else "CHECKS FAILED: %d" % (n_tot - n_pass))
return 0 if n_pass == n_tot else 1
def run():
"""run_all entry point (v757 precedent): expected pattern 21/21 with
verdict DOILY-EXACT."""
rc = main()
n_pass = sum(1 for _n, ok in CHECKS if ok)
fails = [n for n, ok in CHECKS if not ok]
v = _LAST.get("verdict", "")
ok = (rc == 0 and n_pass == len(CHECKS) == 21 and not fails
and v == "DOILY-EXACT")
print("\n[%s] PATTERN GATE: expected 21/21 with verdict "
"DOILY-EXACT; got %d/%d, fails: %s, verdict: %s"
% ("PASS" if ok else "FAIL", n_pass, len(CHECKS),
fails or "none", v))
print("\nCOMBINED ADJUDICATION: %s -- DOILY-EXACT: NN^T = B + 2I "
"entrywise with spec {9, 4^9, 0^5}, so the recovery base "
"rate 2/3 is the unique nontrivial singular value of the "
"canonical duad-to-syntheme channel N/3 (the (2/3)^6 "
"identification typed, pending the six-step composition); "
"Petersen edges = synthemes 15/15 at the q*-point; every "
"census bridge factors exactly as N_code = P_Delta^T "
"N_curve^T P_Gamma -- a duality, not an isomorphism (the "
"inner route stays dead, 0/720); the Arf switch set T6 = the "
"six within-block duads; N/3 doubly stochastic, typed "
"classical, not CPTP. NO RH claim."
% ("PASS" if ok else "FAIL"))
return 0 if ok else 1
if __name__ == "__main__":
raise SystemExit(run())
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