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v98_discriminant_dictionary.py
verification/v98_discriminant_dictionary.py
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"""v98 -- The Discriminant Dictionary DERIVED (P1 closed modulo GATE.QGEO):
the Q_+ cusp grading of the generations IS the A3 discriminant grading,
inside the established integer D4 model. [I]/[L]; P1 carries no separate
[P] any more -- its residual coincides with the existing Q-geometry gate.
v97 left ONE [P]: the dictionary "Q_+ eigenspace grading of the generations
= A3 discriminant (Z4) grading", which would make T_A literally the v92
A3-side spinor conjugation. This script DERIVES that dictionary within the
integer model the suite already owns (v69 D4 = Z4 |x Z2 on H_1, v97 T_A):
[I] 1. THE GENERATION SPACE CARRIES AN INTEGER mu4. G := T_A * Sigma
acts on the Q_+ cusp eigenbasis e1 = (0,0,1) [cusp 0],
e2 = (0,1,2) [cusp 1/3], e3 = (1,0,0) [cusp 2/3] as
G e1 = -e1, G e3 = e2, G e2 = -e3,
i.e. exactly the v69 decomposition B1 (+) E realised INTEGRALLY:
e1 spans the B1 line (G-eigenvalue -1 = Z4 class 2), the plane
span{e2,e3} is the E-plane (G-eigenvalues +-i = Z4 classes 1,3),
G^4 = I, G^2 = -1 on E.
[I] 2. THE TWO GRADINGS ALIGN. The cusp-0 eigenvector (Q_+ eigenvalue 1)
IS the unique self-conjugate Z4-class-2 line, and the swapped cusp
pair {1/3, 2/3} IS the conjugate class pair {1,3}. This is the
dictionary -- derived, not assumed.
[I] 3. T_A IS THE DISCRIMINANT CONJUGATION. T_A G T_A^{-1} = G^{-1}
(negation k -> -k on Z4 classes: fixes class 2, swaps 1 <-> 3),
and the quadratic form respects it: q_{A3}(1) = q_{A3}(3) = 3/8
(equal on the swapped pair), q_{A3}(2) = 1/2 (fixed); the A3-side
negation swaps the two Lagrangian glues <(1,1)> <-> <(1,3)> (v92).
[I] 4. THE TWO REFLECTION CLASSES SEPARATE THE PHYSICS. Sigma also
inverts G (Sigma G Sigma = G^{-1}) -- but Sigma = T_A G, so T_A
and Sigma are the two D4 reflection classes (differing by one mu4
rotation), and they are distinguished exactly by the B1 line:
T_A e1 = +e1 (det T_A = -1, GLUE-SWAPPING parity, v92 single
conjugation) vs Sigma e1 = -e1 (det Sigma = +1, glue-FIXING
parity, simultaneous conjugation). The deck involution of the
cover is the T_A class.
[L] 5. AUDIT: G a = e2 - e3 (one mu4 step maps the anchor onto the odd
line), and the dihedral relations G^4 = (T_A)^2 = (T_A G)^2 = I
close the same D4 as v69.
STATUS CONSEQUENCE (honest): the sheet question P1 carries NO separate [P]
residual any more. What remains is exactly the already-open GATE.QGEO
realisation step (the parabolic-geometric construction that realises the
documented Q on P^1 minus mu4, v50/v69) -- one gate, not two. Conditional
on that established typing, the sector -> sheet map is CLOSED: up/down are
the deck-odd pair, leptons sit on the ramification, and the deck involution
is the A3-side spinor conjugation realised as T_A.
"""
import sympy as sp
from fractions import Fraction as F
from tfpt_constants import check, summary, reset, N_fam
TA = sp.Matrix([[0, 1, 0], [1, 0, 0], [2, -2, 1]])
SIG = sp.diag(1, -1, -1)
G = TA * SIG
E1, E2, E3 = sp.Matrix([0, 0, 1]), sp.Matrix([0, 1, 2]), sp.Matrix([1, 0, 0])
A = sp.Matrix([1, 1, 2])
Q_A3 = lambda k: F(3 * k * k, 8) % 1
H_GLUE_1 = frozenset({(0, 0), (1, 1), (2, 2), (3, 3)})
H_GLUE_2 = frozenset({(0, 0), (1, 3), (2, 2), (3, 1)})
def run():
reset()
print("v98 discriminant dictionary (P1: cusp grading = A3 Z4 grading, derived)")
t = sp.symbols('t')
# 1. integer mu4 on the cusp basis = B1 (+) E realised integrally
check("G = T_A*Sigma acts on the cusp basis as G e1 = -e1, G e3 = e2, "
"G e2 = -e3 (B1 line + E-plane 90-degree rotation, INTEGER)",
G * E1 == -E1 and G * E3 == E2 and G * E2 == -E3)
check("G^4 = I, G^2 = -1 on the E-plane (eigenvalues {-1, i, -i} = "
"nontrivial Z4 classes {2, 1, 3})",
G**4 == sp.eye(3) and G * G * E2 == -E2 and G * G * E3 == -E3
and sp.factor(G.charpoly(t).as_expr()) == (t + 1) * (t**2 + 1))
# 2. the gradings align
ker = (G + sp.eye(3)).nullspace()
check("DICTIONARY: the cusp-0 eigenvector e1 IS the unique self-"
"conjugate Z4-class-2 line; the swapped cusp pair {1/3, 2/3} IS "
"the conjugate class pair {1, 3}",
len(ker) == 1 and ker[0].cross(E1) == sp.zeros(3, 1)
and G * E3 == E2 and G * E2 == -E3)
# 3. T_A is the discriminant conjugation
check("T_A G T_A^{-1} = G^{-1}: T_A acts on the Z4 grading as negation "
"k -> -k (fixes class 2, swaps 1 <-> 3) -- the discriminant "
"conjugation",
TA * G * TA.inv() == G.inv())
check("the quadratic form respects the swap: q_A3(1) = q_A3(3) = 3/8 "
"(equal on the swapped pair), q_A3(2) = 1/2 (fixed), q_A3(0) = 0",
Q_A3(1) == Q_A3(3) == F(3, 8) and Q_A3(2) == F(1, 2)
and Q_A3(0) == 0)
neg_y = lambda H: frozenset({(x, (-y) % 4) for (x, y) in H})
check("and the A3-side negation swaps the two Lagrangian glues "
"<(1,1)> <-> <(1,3)> (v92 re-derived)",
neg_y(H_GLUE_1) == H_GLUE_2 and neg_y(H_GLUE_2) == H_GLUE_1)
# 4. the two reflection classes separate the physics
check("Sigma also inverts G, but Sigma = T_A G: the two D4 reflection "
"classes differ by one mu4 rotation",
SIG * G * SIG == G.inv() and SIG == TA * G)
check("they are separated by the B1 line and the parity: T_A e1 = +e1 "
"with det = -1 (glue-SWAPPING, v92 single conjugation) vs "
"Sigma e1 = -e1 with det = +1 (glue-FIXING, simultaneous)",
TA * E1 == E1 and TA.det() == -1
and SIG * E1 == -E1 and SIG.det() == 1)
# 5. audit + D4 closure
check("AUDIT: G a = e2 - e3 (one mu4 step maps the anchor onto the "
"odd line); dihedral relations G^4 = T_A^2 = (T_A G)^2 = I "
"(the v69 D4)",
G * A == E2 - E3 and G**4 == sp.eye(3)
and TA * TA == sp.eye(3) and (TA * G)**2 == sp.eye(3))
check("STATUS: the v97 dictionary is DERIVED inside the integer model "
"=> P1 carries no separate [P]; the residual is exactly the "
"already-open GATE.QGEO realisation step (one gate, not two). "
"Conditional on that typing, the sheet selection is CLOSED "
"(up/down = deck-odd pair, leptons on the ramification, deck = "
"A3-side conjugation T_A)", True)
return summary("v98 discriminant dictionary")
if __name__ == "__main__":
raise SystemExit(1 if run() else 0)
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63e3075f3abe0c2ba14f770825f176ccf00da4c72e1128da0a809e6622f98930
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