Established in scope
Actual partner map between quarter domains
In the question: Which partner actually belongs to the original seam?
Given chiral source. No selection from P1/P2, no equal responses within one fixed twist, and no identification with affine r0.
Read the exact result, assumptions and evidence
Result
n→−n−1, alpha→1−alpha gives C D_alpha C^-1=−D_(1−alpha). Particles become holes and conversely; normal charge reverses and positive excitation energy is preserved. The unique sea state maps to the other sea state without adding a zero vector within one domain.
Required assumptions
- Given chiral source in both quarter domains
D_alpha=-i∂theta on f(theta+2pi)=exp(2pi i alpha)f(theta), filled negative spectrum and relative particle/hole excitation time; alpha=1/4,3/4. This compares two conjugate domains, not opposite charges in one fixed domain or all P1 sources.
Original evidence
- PROOF.txt lines 154–203
Source checked at this snapshot
Original location and fingerprint
experiments/theory-contracts/seam-partner-original-action-20261015/PROOF.txt
ff7c8dff8939e8380509bff5a34145f935407344a07bda1d65b7b25489a2677c
finding:partner-chiral-quarter-conjugation-state-time